How to Find the Inverse of a Function | IB Math Explained
0:51
YouTubeNail IB
How to Find the Inverse of a Function | IB Math Explained
This inverse function question looks simple at first… but one small algebra mistake can completely change the answer! πŸ˜΅β€πŸ’« In this video, we solve an important IB Math inverse functions question step by step and learn how to find the inverse of a rational function clearly and correctly. We are given: f of x equals to three x minus two ...
1.2K views2 months ago
Shorts
Q) Simplify : sin^(βˆ’1) ((sinπ‘₯+cosπ‘₯)/√2),βˆ’πœ‹/4=π‘₯=πœ‹/4..#class12maths #shivangmathsacademy #cbse
2:06
1.9K views
Q) Simplify : sin^(βˆ’1) ((sinπ‘₯+cosπ‘₯)/√2),βˆ’πœ‹/4=π‘₯=πœ‹/4..#class12maths #shivangmathsacademy
Shivang Maths Academy
CALCULUS: Derivative of Inverse Trigonometry Function | Numberbender
0:49
4 views
CALCULUS: Derivative of Inverse Trigonometry Function | Numberbender
Numberbender
Inverse Function Examples
Introduction to Inverse Functions
12:16
Introduction to Inverse Functions
YouTubeThe Organic Chemistry Tutor
1M viewsFeb 2, 2018
Inverse Functions
10:38
Inverse Functions
YouTubeTranscended Study Hub
2.2K viewsJul 11, 2023
Finding the Inverse of a Function (Step by Step)
1:04
Finding the Inverse of a Function (Step by Step)
YouTubeUnderstand The Math
2.6K views7 months ago
Top videos
How to Find an Inverse Function!
1:15
How to Find an Inverse Function!
YouTubeNumber Nerd
2.3K views2 months ago
Finding the Inverse of an Exponential Function
0:50
Finding the Inverse of an Exponential Function
YouTubevinteachesmath
615 views1 month ago
Find the domain of the function 𝑓(π‘₯)= 𝑠𝑖𝑛^(βˆ’1) (π‘₯^2βˆ’4). Also, find its range.#inversetrigonom
2:06
Find the domain of the function 𝑓(π‘₯)= 𝑠𝑖𝑛^(βˆ’1) (π‘₯^2βˆ’4). Also, find its range.#inversetrigonom
YouTubeShivang Maths Academy
4.3K views1 month ago
Inverse Function Calculator
Inverse Functions on the Calculator
1:42
Inverse Functions on the Calculator
YouTubePiedmontCC Math4U
34.6K viewsSep 25, 2013
How to solve a basic trig equation using inverse trig function (and a calculator)
1:23
How to solve a basic trig equation using inverse trig function (and a calculator)
YouTubebprp math basics
19.3K views2 months ago
How to calculate the Inverse of a Function - Example
0:46
How to calculate the Inverse of a Function - Example
YouTubeMath Turtle
143.5K viewsSep 30, 2021
How to Find an Inverse Function!
1:15
How to Find an Inverse Function!
2.3K views2 months ago
YouTubeNumber Nerd
Finding the Inverse of an Exponential Function
0:50
Finding the Inverse of an Exponential Function
615 views1 month ago
YouTubevinteachesmath
Find the domain of the function 𝑓(π‘₯)= 𝑠𝑖𝑛^(βˆ’1) (π‘₯^2βˆ’4). Also, find its range.#inversetrigonom
2:06
Find the domain of the function 𝑓(π‘₯)= 𝑠𝑖𝑛^(βˆ’1) (π‘₯^2βˆ’4). Also, find its range.#inversetrigonom
4.3K views1 month ago
YouTubeShivang Maths Academy
Q) Simplify : sin^(βˆ’1) ((sinπ‘₯+cosπ‘₯)/√2),βˆ’πœ‹/4=π‘₯=πœ‹/4..#class12maths #shivangmathsacademy #cbse
2:06
Q) Simplify : sin^(βˆ’1) ((sinπ‘₯+cosπ‘₯)/√2),βˆ’πœ‹/4=π‘₯=πœ‹/4..#class12maths #shivangmathsacademy #cbse
1.9K views3 weeks ago
YouTubeShivang Maths Academy
CALCULUS: Derivative of Inverse Trigonometry Function | Numberbender
0:49
CALCULUS: Derivative of Inverse Trigonometry Function | Numberbender
4 views2 weeks ago
YouTubeNumberbender
Q) Simplify : sin(co𝑠𝑒𝑐^(βˆ’1) 17/8)}#class12maths #shivangmathsacademy #cbsemaths #cbsemaths
0:47
Q) Simplify : sin(co𝑠𝑒𝑐^(βˆ’1) 17/8)}#class12maths #shivangmathsacademy #cbsemaths #cbsemaths
3.3K views2 weeks ago
YouTubeShivang Maths Academy
Q) Simplify : tan^(βˆ’1) {√((1βˆ’cosπ‘₯)/(1+cosπ‘₯))}}#class12maths #shivangmathsacademy #cbsemaths
0:51
Q) Simplify : tan^(βˆ’1) {√((1βˆ’cosπ‘₯)/(1+cosπ‘₯))}}#class12maths #shivangmathsacademy #cbsemaths
2.4K views3 weeks ago
YouTubeShivang Maths Academy
1:52
Q) The value of tan[1/2 cos^(βˆ’1) (√5/3)] is (a) (3+√5)/2 (b) (3βˆ’βˆš5)/2(c) (βˆ’3+√g5)/2(d) (βˆ’3βˆ’βˆš5)/2
3.2K views3 weeks ago
YouTubeShivang Maths Academy
1:00
Q) For the inverse trigonometric functions, which of the following Principal Value Branch
1.7K views1 month ago
YouTubeShivang Maths Academy
0:43
Q) If 2cos^(βˆ’1) π‘₯ = 𝑦,then(A) 0β‰€π‘¦β‰€πœ‹(B) βˆ’πœ‹β‰€π‘¦β‰€πœ‹(C) 0≀𝑦≀2πœ‹(D) βˆ’πœ‹β‰€π² ≀ 0 #shivangmathsacademy
7K views1 month ago
YouTubeShivang Maths Academy
1:07
Q) Evaluate tan[cos^(βˆ’1) (tan 3πœ‹/4)].#class12maths #shivangmathsacademy #cbsemaths #class12th
5.6K views1 month ago
YouTubeShivang Maths Academy
0:49
Q) Simplify 𝐭an^(βˆ’πŸ) ( (𝟏 βˆ’π’„π’π’” 𝒙 )/(π’”π’Šπ’ 𝒙 ) )#class12maths # #cbsemaths #class12th
2.1K views3 weeks ago
YouTubeShivang Maths Academy
1:08
Q) Simplify : sin(2sin^(βˆ’1) 0.6)#class12maths #shivangmathsacademy #cbsemaths #class12
4.3K views3 weeks ago
YouTubeShivang Maths Academy
1:05
Draw the graph of 𝑓(π‘₯)=𝑠𝑖𝑛^(βˆ’1) π‘₯, π‘₯∈[βˆ’1/√2, 1/√2]. Also, write range of f(x). #trigonometry
10.8K views4 weeks ago
YouTubeShivang Maths Academy
1:42
Q) Simplify : cot^(βˆ’1) √((1+cos2π‘₯)/(1βˆ’cos2π‘₯)),π‘₯∈(0,πœ‹/2).#maths #cbsemaths #class12 #cbse2026
2.4K views4 weeks ago
YouTubeShivang Maths Academy
1:58
Q) Simplify : tan^(βˆ’1) ((cos2π‘₯βˆ’sin2π‘₯)/(cos2π‘₯+sin2π‘₯)),0=π‘₯=πœ‹/4..#class12maths #shivangmathsaca
2.8K views3 weeks ago
YouTubeShivang Maths Academy
1:08
If 𝑦=𝑠𝑖𝑛^(βˆ’1) π‘₯,βˆ’1≀π‘₯≀0,then the range of 𝑦 is(A) ((βˆ’πœ‹)/2,0)(B) [(βˆ’πœ‹)/2,0](C) [(βˆ’πœ‹)/2,0
3.1K views1 month ago
YouTubeShivang Maths Academy
1:50
Q) Simplify :sin^(βˆ’1) (5/13 cosπ‘₯+12/13 sinπ‘₯)#class12maths #shivangmathsacademy #cbsemaths
2.5K views3 weeks ago
YouTubeShivang Maths Academy
1:14
Finding the Missing Angle with Trig
1.6K views3 weeks ago
YouTubevinteachesmath
See more
Static thumbnail place holder

Short videos

0:51
How to Find the Inverse of a Function | IB Math Explained
1.2K views2 months ago
YouTubeNail IB
1:15
How to Find an Inverse Function!
2.3K views2 months ago
YouTubeNumber Nerd
0:50
Finding the Inverse of an Exponential Function
615 views1 month ago
YouTubevinteachesmath
2:06
Find the domain of the function 𝑓(π‘₯)= 𝑠𝑖𝑛^(βˆ’1) (π‘₯^2βˆ’4). Also, find its range.#inversetrigonom
4.3K views1 month ago
YouTubeShivang Maths Academy
2:06
Q) Simplify : sin^(βˆ’1) ((sinπ‘₯+cosπ‘₯)/√2),βˆ’πœ‹/4=π‘₯=πœ‹/4..#class12maths #shivangmathsacademy #cbse
1.9K views3 weeks ago
YouTubeShivang Maths Academy
0:49
CALCULUS: Derivative of Inverse Trigonometry Function | Numberbender
4 views2 weeks ago
YouTubeNumberbender
0:47
Q) Simplify : sin(co𝑠𝑒𝑐^(βˆ’1) 17/8)}#class12maths #shivangmathsacademy
3.3K views2 weeks ago
YouTubeShivang Maths Academy
0:51
Q) Simplify : tan^(βˆ’1) {√((1βˆ’cosπ‘₯)/(1+cosπ‘₯))}}#class12maths #shivangmathsacademy
2.4K views3 weeks ago
YouTubeShivang Maths Academy
1:52
Q) The value of tan[1/2 cos^(βˆ’1) (√5/3)] is (a) (3+√5)/2 (b) (3βˆ’βˆš5)/2(c) (βˆ’3+√g5)/2(d)
3.2K views3 weeks ago
YouTubeShivang Maths Academy
1:00
Q) For the inverse trigonometric functions, which of the following Principal Value
1.7K views1 month ago
YouTubeShivang Maths Academy
0:43
Q) If 2cos^(βˆ’1) π‘₯ = 𝑦,then(A) 0β‰€π‘¦β‰€πœ‹(B) βˆ’πœ‹β‰€π‘¦β‰€πœ‹(C) 0≀𝑦≀2πœ‹(D) βˆ’πœ‹β‰€π² ≀ 0 #shivangmathsacademy
7K views1 month ago
YouTubeShivang Maths Academy
1:07
Q) Evaluate tan[cos^(βˆ’1) (tan 3πœ‹/4)].#class12maths #shivangmathsacademy
5.6K views1 month ago
YouTubeShivang Maths Academy
0:49
Q) Simplify 𝐭an^(βˆ’πŸ) ( (𝟏 βˆ’π’„π’π’” 𝒙 )/(π’”π’Šπ’ 𝒙 ) )#class12maths # #cbsemaths #class12th
2.1K views3 weeks ago
YouTubeShivang Maths Academy
1:08
Q) Simplify : sin(2sin^(βˆ’1) 0.6)#class12maths #shivangmathsacademy
4.3K views3 weeks ago
YouTubeShivang Maths Academy
1:05
Draw the graph of 𝑓(π‘₯)=𝑠𝑖𝑛^(βˆ’1) π‘₯, π‘₯∈[βˆ’1/√2, 1/√2]. Also, write range of f(x). #trigonometry
10.8K views4 weeks ago
YouTubeShivang Maths Academy
1:42
Q) Simplify : cot^(βˆ’1) √((1+cos2π‘₯)/(1βˆ’cos2π‘₯)),π‘₯∈(0,πœ‹/2).#maths #cbsemaths #class12
2.4K views4 weeks ago
YouTubeShivang Maths Academy
1:58
Q) Simplify : tan^(βˆ’1) ((cos2π‘₯βˆ’sin2π‘₯)/(cos2π‘₯+sin2π‘₯)),0=π‘₯=πœ‹/4..#class12maths #shivangmathsaca
2.8K views3 weeks ago
YouTubeShivang Maths Academy
1:08
If 𝑦=𝑠𝑖𝑛^(βˆ’1) π‘₯,βˆ’1≀π‘₯≀0,then the range of 𝑦 is(A) ((βˆ’πœ‹)/2,0)(B) [(βˆ’πœ‹)/2,0](C) [(βˆ’πœ‹)/2,0
3.1K views1 month ago
YouTubeShivang Maths Academy
1:50
Q) Simplify :sin^(βˆ’1) (5/13 cosπ‘₯+12/13 sinπ‘₯)#class12maths #shivangmathsacademy
2.5K views3 weeks ago
YouTubeShivang Maths Academy
1:14
Finding the Missing Angle with Trig
1.6K views3 weeks ago
YouTubevinteachesmath
Static thumbnail place holder